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Difference between revisions of "Riesel problem 2"
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| [[:Category:Riesel prime 2nd f15|15]] || {{Num|32768}} || {{Num|65535}} || 137 || style="width:4em; background:PaleGreen; | 29 || 29 | | [[:Category:Riesel prime 2nd f15|15]] || {{Num|32768}} || {{Num|65535}} || 137 || style="width:4em; background:PaleGreen; | 29 || 29 | ||
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− | | [[:Category:Riesel prime 2nd f16|16]] || {{Num|65536}} || {{Num|131071}} || 108 || | + | | [[:Category:Riesel prime 2nd f16|16]] || {{Num|65536}} || {{Num|131071}} || 108 || style="width:4em; background:PaleGreen; | 26 || 26 |
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− | | [[:Category:Riesel prime 2nd f17|17]] || {{Num|131072}} || ∞ || | + | | [[:Category:Riesel prime 2nd f17|17]] || {{Num|131072}} || ∞ || 82 || {{Num|{{PAGESINCATEGORY:Riesel prime 2nd f17|R}}}} || ? |
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{{Navbox Riesel primes}} | {{Navbox Riesel primes}} | ||
[[Category:Math]] | [[Category:Math]] |
Revision as of 07:37, 13 May 2021
The 2nd Riesel problem involves determining the smallest Riesel numbers k•2n-1 for 509203 < k < 762701, the first and second Riesel k-values without any possible primes.
m | nmin | nmax | remain | current | target |
---|---|---|---|---|---|
0 | 1 | 1 | 126,748 | 0 | 18,050 |
1 | 2 | 3 | 108,698 | 0 | 27,596 |
2 | 4 | 7 | 81,102 | 0 | 30,503 |
3 | 8 | 15 | 50,599 | 0 | 23,785 |
4 | 16 | 31 | 26,814 | 0 | 13,631 |
5 | 32 | 63 | 13,183 | 0 | 6,613 |
6 | 64 | 127 | 6,570 | 0 | 3,108 |
7 | 128 | 255 | 3,462 | 0 | 1,485 |
8 | 256 | 511 | 1,977 | 0 | 774 |
9 | 512 | 1,023 | 1,203 | 0 | 422 |
10 | 1,024 | 2,047 | 781 | 0 | 228 |
11 | 2,048 | 4,095 | 553 | 0 | 172 |
12 | 4,096 | 8,191 | 381 | 110 | 110 |
13 | 8,192 | 16,383 | 271 | 66 | 66 |
14 | 16,384 | 32,767 | 205 | 68 | 68 |
15 | 32,768 | 65,535 | 137 | 29 | 29 |
16 | 65,536 | 131,071 | 108 | 26 | 26 |
17 | 131,072 | ∞ | 82 | 0 | ? |
Riesel primes
Base = 2 : |
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