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Riesel problem 2, k•2n-1, 509,203 < k < 762,701

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The 2nd Riesel problem involves determining the smallest Riesel numbers k•2n-1 for 509203 < k < 762701, the first and second Riesel k-values without any possible primes.

 
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m nmin nmax remain current target
0 1 1 126,748 16 18,050
1 2 3 108,698 26 27,596
2 4 7 81,102 36 30,503
3 8 15 50,599 45 23,785
4 16 31 26,814 17 13,631
5 32 63 13,183 2 6,613
6 64 127 6,570 1 3,108
7 128 255 3,462 0 1,485
8 256 511 1,977 0 774
9 512 1,023 1,203 1 422
10 1,024 2,047 781 0 228
11 2,048 4,095 553 0 172
12 4,096 8,191 381 110 110
13 8,192 16,383 271 66 66
14 16,384 32,767 205 68 68
15 32,768 65,535 137 29 29
16 65,536 131,071 108 26 26
17 131,072 262,143 82 13 13
18 262,144 524,287 69 16 16
19 524,288 1,048,575 53 11 11
20 1,048,576 2,097,151 42 8 8
21 2,097,152 4,194,303 34 6 6
22 4,194,304 8,388,607 28 6 ≥ 6
23 8,388,608 16,777,215 ≤ 22 0 ≥ 0
unknown 16,777,216 22 0 22

Multi Reservation 21: The current nmax = 8,000,000 as of 2024-03-31.

Riesel primes