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Riesel problem 2, k•2n-1, 762,701 < k < 777,149

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The 3rd Riesel problem involves determining the smallest Riesel numbers k•2n-1 for 762701 < k < 777149, the second and third Riesel k-values without any possible primes.

 
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m nmin nmax remain current target
0 1 1 7,223 0 1,014
1 2 3 6,209 4 1,552
2 4 7 4,657 2 1,746
3 8 15 2,911 4 1,357
4 16 31 1,554 2 803
5 32 63 751 0 380
6 64 127 371 0 168
7 128 255 203 0 88
8 256 511 115 0 50
9 512 1,023 65 2 29
10 1,024 2,047 36 7 7
11 2,048 4,095 29 6 6
12 4,096 8,191 23 6 6
13 8,192 16,383 17 2 2
14 16,384 32,767 15 3 3
15 32,768 65,535 12 2 2
16 65,536 131,071 10 3 3
17 131,072 262,143 7 2 2
18 262,144 524,287 5 0 0
19 524,288 1,048,576 5 1 ≥ 1
unknown 524,288 3 0 3

Multi Reservation 20: The current nmax = 2,000,000 as of 2024-09-06.

Riesel primes